Friday, October 18, 2019
Capacitors in series and parallel ((lab- report )) Coursework
Capacitors in series and parallel ((lab- report )) - Coursework Example During the experiment, the series connection started followed by the parallel connections. At every stage, data collected assisted in computations. The experiment involved the use of voltmeter to measure the voltage drops, a capacitance meter to measure the capacitance and calculations to tabulate data obtained. Series circuit produces the equivalent energy of 0.00031 joules while parallel produces the equivalent energy of 0.00372 joules. Parallel circuits provide more stored energy, thus is the best method to connect capacitors. The experiment derives a capacitance of 5.41 microfarad from the series connection and 68.7microfarad from the parallel connection. This is done by a voltage supply of 10 volts when measured the voltage is 10.42 volts on the series connection and 10.31 volts after parallel connection. This helps determine the amount of average charge in both series and parallel circuits as the series circuit has an average charge of 56.37à µC, and the parallel has an average charge of 708.297 à µC. The series circuit has the lowest voltage drop of 1.56volts while the parallel circuit has the lowest charge at 97.95 à µC. The capacitors in series circuits produce an equivalent capacitance of the sum of the reciprocals of the capacitance of each capacitor. This in turn reduces the amount of energy stored in the capacitors. Parallel circuits produce and equivalent capacitance equal to the sum of the individual capacitance of each capacitor in the circuit. This makes the amount of energy stored in the circuit be more. The series obeys Kirchoffââ¬â¢s Voltage Law that implies the total voltage equivalent to the sum of all the voltage drops within a circuit Swain (2008). From the experiment, I learned that capacitors play a significant role in storing energy in an electric field thus ensuring a steady flow of energy. To store more energy in capacitors, one needs to use the parallel circuit. In application,
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